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Electric Field

Source lecture(s): SC134 Lec2-3

Intuition

A charge creates a field around it; other charges feel forces through that field without touching.

Formal Definition

$\(\vec{E} = \frac{\vec{F}}{q_0}\)$ for a test charge \(q_0\to0\).

Mathematical Formulation

Point charge: $\(\vec{E} = \frac{1}{4\pi\varepsilon_0}\frac{q}{r^2}\hat{r}\)$ Continuous distribution: $\(\vec{E} = \int \frac{1}{4\pi\varepsilon_0}\frac{dq}{r^2}\hat{r}\)$

Derivation

Measure force per unit test charge; superposition allows summation/integration over distributions.

Worked Example

Two equal charges at \(x=\pm a\): on the \(y\)-axis, \(E_x\) cancels, leaving \(E_y = (1/4\pi\varepsilon_0)2qy/(a^2+y^2)^{3/2}\).

Common Mistakes

  • Using \(E = kq/r\) instead of \(kq/r^2\).
  • Forgetting vector direction from source to field point.

Quiz

Q1. What is the unit of electric field?

Answer

N/C or V/m.