Electric Field
Source lecture(s): SC134 Lec2-3
Intuition
A charge creates a field around it; other charges feel forces through that field without touching.
Formal Definition
$\(\vec{E} = \frac{\vec{F}}{q_0}\)$ for a test charge \(q_0\to0\).
Mathematical Formulation
Point charge: $\(\vec{E} = \frac{1}{4\pi\varepsilon_0}\frac{q}{r^2}\hat{r}\)$ Continuous distribution: $\(\vec{E} = \int \frac{1}{4\pi\varepsilon_0}\frac{dq}{r^2}\hat{r}\)$
Derivation
Measure force per unit test charge; superposition allows summation/integration over distributions.
Worked Example
Two equal charges at \(x=\pm a\): on the \(y\)-axis, \(E_x\) cancels, leaving \(E_y = (1/4\pi\varepsilon_0)2qy/(a^2+y^2)^{3/2}\).
Common Mistakes
- Using \(E = kq/r\) instead of \(kq/r^2\).
- Forgetting vector direction from source to field point.
Related Concepts
Quiz
Q1. What is the unit of electric field?
Answer
N/C or V/m.