Contour Integration
Source lecture(s): PHY622 Lec4
Intuition
By closing the integration path in the complex plane, real integrals become contour integrals whose values come from residues.
Formal Definition
The technique of evaluating real integrals by integrating an analytic function over a closed contour in the complex plane.
Mathematical Formulation
Key contour: real axis + large semicircle in the upper half-plane (Jordan's lemma).
Derivation
Choose a contour that simplifies the integral (semicircle, keyhole, wedge). Show the arc contribution vanishes as radius \(\to\infty\); the real integral equals \(2\pi i\) times enclosed residues.
Worked Example
\(\int_{-\infty}^\infty \frac{dx}{1+x^2}=\pi\) via semicircle enclosing \(z=i\).
Common Mistakes
- Forgetting to check arc contributions vanish.
- Choosing the wrong half-plane for oscillatory integrals.
Related Concepts
Quiz
Q1. When does Jordan's lemma apply?
Answer
For integrals of \(e^{ikz}f(z)\) with \(k>0\) and \(f\to0\) on a large semicircle.